Question

"EMATICS
M.M. : 20
1.
According to the diagram :
D
Let AC = 3, BC = 4, AB = 5 and line AB is parallel to CP then the length of perpendicular from P on
AB is

Answer 1

Answer:

QUESTION

"EMATICS

M.M. : 20

1.

According to the diagram :

D

Let AC = 3, BC = 4, AB = 5 and line AB is parallel to CP then the length of perpendicular from P on

AB is

ANSWER

Given, ∠A=90∘

Given, ∠A=90∘By Pythagoras theorem,

Given, ∠A=90∘By Pythagoras theorem,BC2=AB2+AC2

Given, ∠A=90∘By Pythagoras theorem,BC2=AB2+AC2BC2=52+122

Given, ∠A=90∘By Pythagoras theorem,BC2=AB2+AC2BC2=52+122BC=13 cm

Given, ∠A=90∘By Pythagoras theorem,BC2=AB2+AC2BC2=52+122BC=13 cmArea of triangle = 21×base×height

Given, ∠A=90∘By Pythagoras theorem,BC2=AB2+AC2BC2=52+122BC=13 cmArea of triangle = 21×base×heightThus, 21AB×AC=21AD×BC

Given, ∠A=90∘By Pythagoras theorem,BC2=AB2+AC2BC2=52+122BC=13 cmArea of triangle = 21×base×heightThus, 21AB×AC=21AD×BC5×12=13×AD

Given, ∠A=90∘By Pythagoras theorem,BC2=AB2+AC2BC2=52+122BC=13 cmArea of triangle = 21×base×heightThus, 21AB×AC=21AD×BC5×12=13×ADAD=1360 cm.

hope it helps

Answer 2

Step-by-step explanation:

yooo

umm according to me after solving this question according to the paralleogram theorem....the answer of this question is surely::::::> 2.4