Math, asked by kirti222, 3 months ago

EMERGENCY!!!!

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Answered by diyapanicker
2

Answer:

Given, y² + 1/y² = 23

⇒ (y + 1/y)² - (2 × y × 1/y) = 23

⇒ (y + 1/y)² - 2 = 23

⇒ (y + 1/y)² = 23 + 2

⇒ (y + 1/y)² = 25

⇒ y + 1/y = - 5,

where we take the negative value only.

∴ y³ + 1/y³

= (y + 1/y)³ - (3 × y × 1/y)(y + 1/y)

= (- 5)³ - {3 × (- 5)}

= - 125 + 15

= - 110

Identity rule :

a³ + b³ = (a + b)³ - 3ab(a + b)

I hope it helps!

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