Physics, asked by div64, 10 months ago

emergency call for genius(only genius like me)
The amount of work done in pumping water
out of a cubical vessel of height 1 m is nearly
(g = 10 ms 2) Why we take mgh/2
(a) 10 J (b) 500J
(c) 500 J
(d) 5000 J

Answers

Answered by aishwaryamore

Answer:

if you r a genius then solve it by self

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Answered by aditya742831

Answer:

5000j is correct one

Explanation:

first draw the diagram

then u must know work done =-change in potential energy

then work done =mgh

mass=density ×volume

(1000kg/m^3)

1000×1=1000

substitute the value to get 10^4

I hope it will be helpfull for you dear

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