emergency call for genius(only genius like me)
The amount of work done in pumping water
out of a cubical vessel of height 1 m is nearly
(g = 10 ms 2) Why we take mgh/2
(a) 10 J (b) 500J
(c) 500 J
(d) 5000 J
Answers
Answered by
4
Answer:
if you r a genius then solve it by self
div64:
rai
Answered by
5
Answer:
5000j is correct one
Explanation:
first draw the diagram
then u must know work done =-change in potential energy
then work done =mgh
mass=density ×volume
(1000kg/m^3)
1000×1=1000
substitute the value to get 10^4
I hope it will be helpfull for you dear
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