Physics, asked by div64, 1 year ago

emergency call for genius(only genius like me)
The amount of work done in pumping water
out of a cubical vessel of height 1 m is nearly
(g = 10 ms 2) Why we take mgh/2
(a) 10 J (b) 500J
(c) 500 J
(d) 5000 J​

Answers

Answered by aishwaryamore
4

Answer:

if you r a genius then solve it by self


div64: rai
aishwaryamore: what the
aishwaryamore: i am not a rai
aishwaryamore: tell me how many points do u have
aditya742831: hey div i m also in 10 yaar
aishwaryamore: ok
div64: yo
div64: are u still there?
aishwaryamore: ya
aditya742831: tat be hap
Answered by aditya742831
5

Answer:

5000j is correct one

Explanation:

first draw the diagram

then u must know work done =-change in potential energy

then work done =mgh

mass=density ×volume

(1000kg/m^3)

1000×1=1000

substitute the value to get 10^4

I hope it will be helpfull for you dear


aditya742831: sorrt
aishwaryamore: mister
aditya742831: sorry
aditya742831: tell miss
aishwaryamore: know you r in good toon
aditya742831: so what
aishwaryamore: get lost dear
aditya742831: chal ht u came to me not me to u ok
aishwaryamore: o hello u came to me to chat
aishwaryamore: bajurbut
Similar questions