Question

emergency emergent speed of bullet​

Answer 1

AnswEr :

Emergent Speed of the Ball is 30√10 m/s

Explanation :

From the Question,

• Mass of the Bullet (M) = 25.09 g

• Initial Velocity (u) = 300 m/s

• Penetration Distance (s) = 2 cm

To finD

Emergent Speed to the bullet

According to the Question,

Final Kinetic Energy is 10 percent of the Initial KE

We know that,

$\boxed{\boxed{\sf K = \dfrac{1}{2}Mv^2}}$

Now,

Final KE = 10 % of Initial KE

(Putting the values)

$\longrightarrow \: \sf \: \dfrac{1}{2} \times 25.09 \times {v}^{2} = \dfrac{1}{2} \times 25.09 \times (300) {}^{2} \times \dfrac{10}{100} \\ \\ \longrightarrow \: \sf v {}^{2} = \dfrac{300 \times 300 \times 10}{100} \\ \\ \longrightarrow \: \sf \: {v}^{2} = 300 \times 3 \times 10 = 9000 \\ \\ \large{ \longrightarrow \: \boxed{ \boxed{ \sf \: v =30 \sqrt{10} \: \: {ms}^{ - 1} }}}$