EMERGENCY
two objects of masses m1 and m2 exert a force f on each other when they were separated by distance r. what happened when 1) mass m1 is doubled 2) the distance between them is halved?
it's for 3 marks
no spamming I will report
please answer ASAP I WILL MARK YOU AS BRAINLIEST
Answers
Given, two objects of masses m₁ and m₂ are separated by a distance r exert a force f on each other.
The force between the objects is given by,
⇒ f = Gm₁m₂ / r² ...(1)
We have to find the force between them when,
[i] Mass m₁ is doubled
All other physical quantities will remain same except m₁ which will become 2m₁
Let's find the force now,
⇒ Force = G(2m₁m₂) / r²
⇒ Force = 2 Gm₁m₂ / r²
⇒ Force = 2 f [ from (1) ]
It is clear that when mass m₁ is doubled, the force between them will also get doubled.
[ii] Distance r is halved.
All other physical quantities will remain same except the distance between them becomes r/2
So, Let us find the force,
⇒ Force = Gm₁m₂ / (r/2)²
⇒ Force = Gm₁m₂ / (r² / 4)
⇒ Force = 4 Gm₁m₂ / r²
⇒ Force = 4 f [ from (1) ]
Hence, when the distance between them is halved, then the force becomes 4 times.
Answer:
Given, two objects of masses m₁ and m₂ are separated by a distance r exert a force f on each other.
The force between the objects is given by,
⇒ f = Gm₁m₂ / r² ...(1)
We have to find the force between them when,
[i] Mass m₁ is doubled
All other physical quantities will remain same except m₁ which will become 2m₁
Let's find the force now,
⇒ Force = G(2m₁m₂) / r²
⇒ Force = 2 Gm₁m₂ / r²
⇒ Force = 2 f [ from (1) ]
It is clear that when mass m₁ is doubled, the force between them will also get doubled.
[ii] Distance r is halved.
All other physical quantities will remain same except the distance between them becomes r/2
So, Let us find the force,
⇒ Force = Gm₁m₂ / (r/2)²
⇒ Force = Gm₁m₂ / (r² / 4)
⇒ Force = 4 Gm₁m₂ / r²
⇒ Force = 4 f [ from (1) ]
Hence, when the distance between them is halved, then the force becomes 4 times.
Explanation:
Hope this answer will help you.✌️