Question

EMF of an electrical cell is 2 volt.A 10 ohm resistance is joined at its two ends then potential difference is measured 1.6 volt.find our the internal resistance and lost volt
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Answer 1

Internal resistance of the battery will be 2.5 ohm and lost voltage will be 0.4 volt

Explanation:

We have given emf of the electric cell E = 2 volt

External resistance R = 10 ohm '

Potential difference across 10 ohm resistance = 1.6 volt

So current in the circuit $i=\frac{potential\ difference}{resistance}=\frac{1.6}{10}=0.16A$

Now we know that $V=E-ir$, here r is internal resistance

So $1.6=2-0.16\times r$

$r=2.5ohm$

So internal resistance of the battery will be 2.5 ohm

Lost voltage will be 2-1.6 = 0.4 volt

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