Question

EMF of the cell balance against a length of 217 cm of potentiometer wire when the cell is shunted by a resistance of 15 ohm the balancing length is 200 cm find the internal resistance of the cell

Answer 1

Answer:

Internal Resistance=r

r=R (L1/L2-1)

•10 {L1/250-1}=5 {L1/200-1}

>L1{1000/3Cm}

and r=10

{1000/3×250-1}=10/3ohm.

Explanation:

mark as brainliest