EMF of the following cell is 0.3305V:Zn/Zn2+(0.1M)llCd2+(C)/Cd.Calculate the concentration (C) of the Cd2+ Given that: Eº (Zn2+/Zn) = -0.76 V and E°(Cd2+/Cd)=-0.40V
Answers
Answered by
0
Answer:
7.0 is the answer
Explanation:
please mark me as brainlist
Similar questions