Question

Emissive power of an ideal black body at 127°c is
e. The temperature at which it increases to 102 is

Answer 1

here is your answer mate

97 degree Celsius

hope it helps

plz plz mark as brainliest plz

Answer 2

The temperature is 477 K.

Explanation:

Given that,

Power = e

Temperature = 127°C

Increases power = 102%

We need to calculate the increases power

$E'=e+1.02e$

$E'=2.02e$

We need to calculate the temperature

Using Stefan's law

$E=\sigma T^4$

We can use

$\dfrac{E}{E'}=\dfrac{T^4}{T'^4}$

Put the value into the formula

$\dfrac{e}{2.02e}=\dfrac{127^4}{T'^4}$

$\dfrac{1}{2.02}=\dfrac{(127+273)^4}{T'^4}$

$T'^4=2.02\times(127+273)^4$

$T'=(2.02)^{\dfrac{1}{4}}\times400$

$T'=477\ K$

Hence, The temperature is 477 K.

Learn more :

Topic : Stefan's law

https://brainly.in/question/7733347