Question

Empirical formula of a compound is C2H4O. If its
empirical formula weight is equal to its vapour density,
calculate the molecular formula of the compound.​

Answer 1

Answer:

C4H8O2

Explanation:

weight of empirical formula=2×12+4×1+16=44g

molecular weight =2(vapour density)

given vapour density= empirical weight

molecular weight =2(44)=88g

n=molecular weight /empirical weight

n=88/44=2

molecular formula = (empirical formula)n = (C2H4O)2 =C4H8O2

Hope this will help u and this is correct