Empirical formula of a compound is C2H5O and it's molecular weight is 90 .molecular formula of the compound is
A. C2H5O
B. C3H6O3
C. C4H10O2
D. C5H14O2
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3
Answer:
option 'c' is correct.
Explanation:
emprical formula=>C2H5O
mass=>90u
therefore,molecular formula is given by,
C2xH5xOx (x is no. of atoms.)
since Mass of 2carbon is 12u*2=24u
therefore,
mass of x carbon atom=24x u.
Similarly,
mass of x hydrogen atom=5x u
and
mass of x oxygen atom=16x u
now,
atq
24x+5x+16x=90
45x=90
x=2
putting x in formula we get....
C4H10O2
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