Question

Empirical formula of a compound is C2H6O. If its empirical formula is twice

    its vapour density, calculate the molecular formula of the compound.​

Answer 1

Answer:

C2H6O

Explanation:

Emprical mass of C2H6O  = (2x12)+(6x1)+(1x16)

                      = 24 + 6 + 16

                      = 46

Given that,

twice Vapour Density = Emprical formula (i.e Emprical mass)

Therefore, 2 x VD = 46

Hence, VD = 46/2 = 23

Now,

Molecular Mass  = 2 x VD

 = 2 x 23

 = 46

Now to find number (n),

n = Molecular mass/Emprical Mass

 = 46/46 = 1

Hence, Molecular Formula is same as Emprical Formula.

= $C_{2}$$H_{6}$$O$

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Answer 2

Given: Empirical formula of a compound is C2H6O. If its empirical formula is twice its vapour density.

To find: We have to find out the molecular formula of the compound.

Solution:

Emprical mass of $C_2H_6O$ will be-

(2x12)+(6x1)+(1x16)

= 24 + 6 + 16

= 46

Now given that twice vapour density = emprical formula (i.e emprical mass)

Therefore, 2 x VD = 46

Hence, VD = 46/2 = 23

Now,

Molecular mass will be twice the vapour density.

= 2 x VD

= 2 x 23

= 46

Now n will be a ratio of molecular mass to emperical mass.

n = molecular mass/emprical mass

= 46/46 = 1

Hence, molecular formula is same as emprical formula.

So, molecular formula of the compound is $C_2H_6O$.