empirical formula of a compound is CH3N and .if the empirical formula weight is equal to one fourth of its vapour density then find out the molecular formula of the compound
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Empirical formula of a compound = CH3N
Empirical formula weight = 1/4 x vapour density
29 = 1/4 x Molecular mass/2
Molecular mass = 29 x 8 = 232g
n = Molecular mass / empirical formula weight = 232/29 = 8
Molecular formula = n x empirical formula = 8 x CH3N = C8H24N8
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