Chemistry, asked by gattugkswamy, 3 months ago

empirical formula of c18 h36 o2

Answers

Answered by PARCH0

The n-Factor is 2 .

E.F = M.F/N-Factor

=> C18H36O2/2

=> C9H18O

Answered by udayadithya123

Answer:

C9H18O IS THE EMPIRICAL FORMULA.

Explanation:

FIRST OF ALL, WHAT IS AN EMPIRICAL FORMULA, SHORT FORM OF MOLECULAR FORMULA.

IN C18H36O2 CAN BE WRITEN AS

C9H18O

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