Question

empt any hive questions :- 8g of pure calcium is treated with 50g of pure HCl to give Cacl, and Ha.​

Answer 1

Answer:

Reaction:

Mg+2HCl⟶MgCl2+H2

Gaseous product is hydrogen

H2+Cl2⟶2HCl

AmountofpureMgin50gsample=45g.

Numberofmoles=1.875

1moleMg⟶1moleH2

1.875moleMg⟶1.875H2

1.875molesH2⟶2×1.875moles of HCl=3.75moles

Answer 2

Explanation:

Well, where is your stoichiometric equation?

Ca(s)+2HCl(g)→CaCl2(s)+H2(g)↑

nCa=8∙g40.08∙g∙mol−1=0.200∙mol

nHCl=50∙g36.46∙g∙mol−1=1.37∙mol

Clearly, hydrogen chloride is in stoichiometric excess…and thus the metal is the limiting reagent. Practically, we would use a SOLUTION of hydrochloric acid to achieve this reaction, rather than pfaffing about with volumes of noxious gas…