Math, asked by darshikabhanwar, 3 months ago

EN
1
LEXAMPLE 3 In each of the following, determine the value of k for which the given value is a solution
of the equation:
(1) kor? + 2x – 3 = 0, x = 2
(ii) 3x2 + 2kx – 3 = 0, x = -
2
(iii) x2 + 2ax - k = 0, x = -a
(i) Since 2 is a montof the giyen equation. Therefore, it satisfies the equation
ON​

Answers

Answered by FareehaAfroz
0

Answer:

ii) k=-15/4

Step-by-step explanation:

put x=-2 equation

3×(-2)×2+2k×(-2)-3=0

-12-4k-3=0

-4k=15

k=-15/4

ans check

-12-4×-15/4-3

-15+15=0

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