Chemistry, asked by surendravijaya73, 7 months ago

EN of the element (A) is E, and IP is E. Hence EA will be
(A) 2E-E
(B) E,-E2
(C) E,-2E2
(D) (E,+E2)/2

Answers

Answered by Anonymous

1

Answer:

Explanation:

EN of the element (A) is E1 and IP is E2. Hence EA will be. [A] 2E1-E2. [B] E1-E2. [C] E1-2E2. [D] (E1+E2)/.

Hope the answer is correct.

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