Math, asked by JosueSalva, 11 months ago

En un establo hay pollos y conejos; en total hay 18 orejas y 66 patas; si C es la cantidad de conejos y P la cantidad de pollos, el sistema de ecuaciones que permite contestar, ¿cuánt animales de cada tipo hay?, es:

a) C+P=18 B)2C+P=18 C)2C=18 D)2C+P=19 E)2C-P=18

a) 2C+P=66 b)2C-P=18 c)4C+2P=66 d)4C+2P=66 e) 2C+P=66

Answers

Answered by Anonymous
5

Answer:

translation for my frnds who don't know Spanish -

In a stable there are chickens and rabbits; altogether there are 18 ears and 66 legs; if C is the number of rabbits and P the number of chickens, the system of equations that allows us to answer, how many animals in each

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