Question

एन ऑब्जेक्ट थ्रोन वर्टिकली अपवर्ड राइस टू 5 मीटर कैलकुलेट योर सिटी विद विच द ऑब्जेक्ट वास थ्रोन अपवर्ड ​

Answer 1

Answer:

Distance travelled, s = 10 m

Final velocity, v = 0 m/s

g = -9.8 m/s

2

1) Using,

v

2

−u

2

=2gs

u

2

=196

u=14m/s, where u is the velocity with which the object is thrown upwards.

2) Using,

v=u+gt

t=

g

v−u

=1.43 sec

Answer 2

Answer:

I hope this answer is write

Step-by-step explanation:

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Class 11

>>Physics

>>Motion in a Straight Line

>>Free Fall

>>An object thrown vertically...

Question

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An object thrown vertically up from the ground passes the height 5 m twice in an interval of 10 s. What is its time of flight?

A

28

s

B

86

s

C

104

s

D

72

s

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Solution

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Correct option is

C

104

s

The object has flight height (s−5) m in

2

10

s= 5s

The object is descending at the same time= 5s

Using,

s=ut+

2

1

at

2

s−5=0×5+

2

1

×9.8×5

2

s=127.5 m

Time taken to travel vertically 127.5 m,

=>127.5=0×t+

2

1

×9.8×t

2

t

2

=26.02s

t= 5.1 s

Therefore total time of flight is= 2×5.1 = 10.2s

104

s