Math, asked by rudra2201, 20 days ago

ench at the non-parallel sides is 5 cm, find the area of the trapezium. The parallel sides of a trapezium are 20 cm and 10 cm and the length of each of the song des is 13 cm. Find the area of the trapezium. morale in a shape of a trapezium with area 10m2 The parallel​

Answers

Answered by sonysony28050
0

Base of triangle =

Base of triangle = 2

Base of triangle = 220−10

Base of triangle = 220−10

Base of triangle = 220−10 =5

Base of triangle = 220−10 =5Height of the triangle and rectangle (h)

Base of triangle = 220−10 =5Height of the triangle and rectangle (h) 2

Base of triangle = 220−10 =5Height of the triangle and rectangle (h) 2 =13

Base of triangle = 220−10 =5Height of the triangle and rectangle (h) 2 =13 2

Base of triangle = 220−10 =5Height of the triangle and rectangle (h) 2 =13 2 −5

Base of triangle = 220−10 =5Height of the triangle and rectangle (h) 2 =13 2 −5 2

Base of triangle = 220−10 =5Height of the triangle and rectangle (h) 2 =13 2 −5 2

Base of triangle = 220−10 =5Height of the triangle and rectangle (h) 2 =13 2 −5 2 ⇒(h)

Base of triangle = 220−10 =5Height of the triangle and rectangle (h) 2 =13 2 −5 2 ⇒(h) 2

Base of triangle = 220−10 =5Height of the triangle and rectangle (h) 2 =13 2 −5 2 ⇒(h) 2 =144

Base of triangle = 220−10 =5Height of the triangle and rectangle (h) 2 =13 2 −5 2 ⇒(h) 2 =144⇒h=12

Base of triangle = 220−10 =5Height of the triangle and rectangle (h) 2 =13 2 −5 2 ⇒(h) 2 =144⇒h=12Area of trapezium =

Base of triangle = 220−10 =5Height of the triangle and rectangle (h) 2 =13 2 −5 2 ⇒(h) 2 =144⇒h=12Area of trapezium = 2

Base of triangle = 220−10 =5Height of the triangle and rectangle (h) 2 =13 2 −5 2 ⇒(h) 2 =144⇒h=12Area of trapezium = 21

Base of triangle = 220−10 =5Height of the triangle and rectangle (h) 2 =13 2 −5 2 ⇒(h) 2 =144⇒h=12Area of trapezium = 21

Base of triangle = 220−10 =5Height of the triangle and rectangle (h) 2 =13 2 −5 2 ⇒(h) 2 =144⇒h=12Area of trapezium = 21 ×(sum of parallel sides) × (height)

Base of triangle = 220−10 =5Height of the triangle and rectangle (h) 2 =13 2 −5 2 ⇒(h) 2 =144⇒h=12Area of trapezium = 21 ×(sum of parallel sides) × (height) =

Base of triangle = 220−10 =5Height of the triangle and rectangle (h) 2 =13 2 −5 2 ⇒(h) 2 =144⇒h=12Area of trapezium = 21 ×(sum of parallel sides) × (height) = 2

Base of triangle = 220−10 =5Height of the triangle and rectangle (h) 2 =13 2 −5 2 ⇒(h) 2 =144⇒h=12Area of trapezium = 21 ×(sum of parallel sides) × (height) = 21

Base of triangle = 220−10 =5Height of the triangle and rectangle (h) 2 =13 2 −5 2 ⇒(h) 2 =144⇒h=12Area of trapezium = 21 ×(sum of parallel sides) × (height) = 21

Base of triangle = 220−10 =5Height of the triangle and rectangle (h) 2 =13 2 −5 2 ⇒(h) 2 =144⇒h=12Area of trapezium = 21 ×(sum of parallel sides) × (height) = 21 ×(10+20)×(12)

Base of triangle = 220−10 =5Height of the triangle and rectangle (h) 2 =13 2 −5 2 ⇒(h) 2 =144⇒h=12Area of trapezium = 21 ×(sum of parallel sides) × (height) = 21 ×(10+20)×(12) =180 sq.cm

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