Question

end of
pe
diameter of circle
is (10), find
a
of one
x² ty? Qi-44+1
other end.
ayt1 = 0​

Answer 1

Answer:

One end of diameter of the circle =(3,2)

Center of the circle =(0,0)

Let, the other end of diameter of the circle =(x,y)

Since , center is the mid-point of the diameter of the circle

(0,0)=(

2

3+x

,

2

2+y

)

⟹

2

3+x

=0 and

2

2+y

=0

⟹3+x=0 and 2+y=0

⟹x=−3 and y=−2

Hence, the other end of diameter of the circle =(−3,−2)

Step-by-step explanation:

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