Question

Ends A and B are connected to positive and negative terminals of a cell of emf 12V respectively.
The value of voltage shown by voltmeter of negligible resistance is

Answer 1

Ans. is 6 V .... solutionis in the attached pic ... :)

Answer 2

Given:

When a voltage source of 12v is applied at the terminals, the circuit becomes like above.

Total resistance of the circuit = 6 + 6 + 6 + 6 = 24 ohms

The current I flowing through the circuit from terminals A to B is,

$I=\frac { V }{ R }$

$I=\frac { 12 }{ 24 } =0.5A$

Voltage reading shown in the voltmeter $V = I \times R$

$V = 0.5 \times (6+ 6) = 0.5 \times 12 = 6 Volts$