Physics, asked by Rajendragadhwal2691, 1 year ago

Enemy charcoal consists of 20 turns of wire each of area 0.09 m square and total resistance 15 ohm equal rights in a magnetic field of 0.5 tesla at a constant frequency of 150 upon by hertz calculate the value of maximum as well as average induced emf produced in the coil

Answers

Answered by sureshsharma4084
0

Hello!

The emf value can be calculated using the following equation

 E = NBASinwt

here N is the number of turns = 20

B is the magnetic field = 30 X 10-3 T

A is the area of the circular coil = πr2 = 3.14*(0.08)2

w is the angular frequency = 50 rad/s

t is the time

 

(1) we can calculate the maximum emf value using sinwt = 1, in equation (1). So,

 

 E0 = NBAw = NBπr2w

 

(2) the average emf is given by the relation,  

 Eav = NBA(sinwt)av = 0  [as (sinwtav = 0]

(3) the rms value of the emf is written as

 Erms = E0/√2

(4) the power dissipated would be

 P = I2R = (Erms)2/2 

 

by substituting the respective values, we can get the required answers

Hope it will help you plz mark it as BRAINLIEST ANSWER!!

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