energy difference between 5th and 4th orbits is
Answers
Answer:
Answer
It is given that the quantisation rule followed in aliens' planet is as follows:
mvr=
4π
nh
The change in quantisation rule will not affect the energy difference.
The energy difference (in eV) is given by the expression =E
n
−E
n
′
=−13.6×[
n
2
1
−
n
′2
1
]
We need to find the energy difference between fourth and second orbits.
E
4
−E
2
=−13.6[
4
2
1
−
2
2
1
]
E
4
−E
2
=−13.6×[0.0625−0.25]=−13.6×(−0.1875)=2.55 eV
Hence, the energy difference between fourth and second orbits for H atom is 2.55 eV.
Answer:
It is given that the quantisation rule followed in aliens' planet is as follows:
mvr=
4π
nh
The change in quantisation rule will not affect the energy difference.
The energy difference (in eV) is given by the expression =E
n
−E
n
′
=−13.6×[
n
2
1
−
n
′2
1
]
We need to find the energy difference between fourth and second orbits.
E
4
−E
2
=−13.6[
4
2
1
−
2
2
1
]
E
4
−E
2
=−13.6×[0.0625−0.25]=−13.6×(−0.1875)=2.55 eV
Hence, the energy difference between fourth and second orbits for H atom is 2.55 eV.
Explanation:
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