Energy of a charged capacitor is U. Now it is removed from a battery and then is connected to another identical uncharged capacitor in parallel. What will be the energy of each capacitor now ?(A) 3U/2
(B) U
(C) U/4
(D) U/2
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Answer:
(C) U/4
Explanation:
Energy of a charged capacitor = U
Let the charge on capacitor be = Q.
Thus, the energy Stored : Q²/2C
The flow of charge will be such that the potential difference and total charge (Q) across the capacitor remains same.
Hence,
Potential difference across the capacitor-
V = Q/2C
Energy in each capacitor - 1/2C V²
= 1/2C × (Q/2C)²
= 1/4 × (1/2 Q²/C)
= 1/4U
Therefore, the energy of each capacitor will be U/4 .
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