Question

Energy of a mole of radio wave photons with a frequency of 909 khz is

Answer 1

Energy = hf

Where h = planks constant

f = frequency

Planks constant = 6.62 × 10 ⁻³⁴

f = 909kHz this equals :

909000Hz


Energy = 909000 × 6.62 × 10⁻³⁴

= 6.01758 × 10⁻²⁸ Joules

Answer 2

Answer:

Explanation:

Energy = hf

Where h = planks constant

f = frequency

Planks constant = 6.62 × 10 ⁻³⁴

f = 909kHz this equals :

909000Hz

Energy = 909000 × 6.62 × 10⁻³⁴

= 6.01758 × 10⁻²⁸ Joules