Question

Energy of a particle executing shm....potential energy....class 11......please explain breifly
you'll get 50 points

Answer 1

✔️✔️ANSWER ✔️✔️


✔️✔️ENERGY OF PARTICAL EXECUTING SHM ✔️✔️

a partical during SHM execute both KE AND PE

POTENTIAL ENERGY

happen due to dispalcement of partical form mean position

U= 1/2 KX^2

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U=1/2 m omega ^2 x^2

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a= - omega square y

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f= - m omega square y

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dw = m omega square y dy

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Answer 2

Answer:

The energy of a particle executing simple harmonic motion is given by the equation E=Ax2+Bv2 where x is the displacement from mean position x=0 and v is the velocity of the particle at x.