Physics, asked by atmanraja8898, 1 year ago

Energy of a photon having wavelength 3000 nm will be (h = 6.626 × 10–34 js)

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Answered by Geniusshivanshu1111
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It may be a correct answer .
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Answered by PoojaBurra
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Energy of photon is 6.626 ×  {10}^{ - 20} J

Given - Value of h and wavelength

Find - Energy of photon

Solution - Energy of photon can be calculated by the formula -

Energy = planck's constant × frequency

Also, frequency is given by the formula -

Speed of light = frequency × wavelength

So, the on combining the two equations, we get equation of energy as -

Energy = planck's constant × speed of light /wavelength

Now, converting wavelength to metres.

As per the known fact, 1 nm =  {10}^{ - 9} m

So, 3000 nm = 3 ×  {10}^{ - 6} m

Keep the values in formula to find the energy of photon

Energy =  \frac{6.626 \times  {10}^{ - 34}  \times 3 \times  {10}^{8} }{3 \times  {10}^{ - 6} }

On solving we get the energy of photon as -

Energy = 6.626×  {10}^{ - 20} J

Hence, the energy of photon is 6.626 ×  {10}^{ - 20} J

#spj2

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