Energy of a photon having wavenumber 1.00 cm^-1 is?
A) 6.62x10^-34
B) 1.99x10^-23
C) 6.62x10^-32
D) 6.62x10^-36
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Hey.
Here is the answer.
As energy of a photon , E = hf = hc/λ.
Here h = 6.626×10-34 Js is a universal constant called Planck's constant.
As wavelength = 1 cm^-1 = 0.01 /m
speed of light ,c = 3×10^8 m/s
So, Energy = 6.626×10^-34×3×10^8 /0.01
or, energy of photon =1987.8×10^-26 J
or, energy of photon = 1.99×10^-23 J
So, (B) is the correct choice.
Thanks.
Here is the answer.
As energy of a photon , E = hf = hc/λ.
Here h = 6.626×10-34 Js is a universal constant called Planck's constant.
As wavelength = 1 cm^-1 = 0.01 /m
speed of light ,c = 3×10^8 m/s
So, Energy = 6.626×10^-34×3×10^8 /0.01
or, energy of photon =1987.8×10^-26 J
or, energy of photon = 1.99×10^-23 J
So, (B) is the correct choice.
Thanks.
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