Question

Energy of an electron in an excited state of hydrogen atom is -3.4ev. Calculate angular momentum of electron according to bohr's theory

Answer 1

Answer:

angular momentum = nh/2π

n= 2

L = h/π

Answer 2

$E = - 13.6 \frac{ {z}^{2} }{ {n}^{2} } \\ \\ - 3.4 = \frac{ - 13.6}{ {n}^{2} } \\ \\ {n}^{2} = \frac{ - 13.6}{ - 3.4} \\ \\ {n}^{2} = 4 \\ n = \sqrt{4} \\ n = 2$

Angular momentum (mvr) =

$mvr = \frac{nh}{2\pi} \\ \\ mvr = \frac{2h} {2\pi} \\ \\ mvr = \frac{h}{\pi}$