Question

Energy of an electron is given by E = -2.178×10-18 J Z2/n2. Wavelength of light required to excite an electron in an hydrogen atom from level n =1 to n = 2 will be (h = 6.62 ×10−34Js and c = 3.0 ×108ms−1

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Answer 1

Answer:

Solution:

We know that energy of an electron can be calculated using Planck relation

E = hc/λ     …………… (i)

But in the question it is given that

E = -2.178×10^-18 J Z2 (1/n₁² -1/n₂²) …………(ii)

On comparing both the equations we get,

hc /λ =-2.178×10^-18 J Z2(1/n₁² -1/n₂²) ………….(iii)

On substituting the values

h =6.62 ×10−34Js

c = 3.0 ×108ms−1

n₁= 1 & n₂= 2

In equation (iii) and calculating for the value of λ we get,

λ =1.214 ×10^−7m

Hope it will help you

Answer 2

Answer:

How much energy is released in the following reaction?

1H2 + 1H2 = 2He4

If the B.E./Nucleon of 1H2 and 2He4 are 1.123 MeV and 7.2 MeV respectively.

Explanation:

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