Question

Energy of an electron is given by
E=-2.178x10^-18J(Z²/n²). Wavelength of light
required to excite an electron in an hydrogen
atom from level n = 1 to n = 2 will be
(h=6.62x10-34 Js and c=3.0x108 ms )
(a) 1.214x10^-7m (b) 2.816x10^-7m
(©) 6.500x10^-7m (d) 2.816x10^-7m.​

Answer 1

Answer:

(a) 1.214 x 10^-7

Explanation:

first calculate energy

E= -2.178 x 10^-18 [1/n1^2 - 1/n2^2]

E= -2.178 x 10^-18 [1/1 - 1/4]

E= -2.178 x 10^-18 x 3/4 --------(1)

now,

we know that

E=hc/ λ

-2.178 x 10^-18 x 3/4 = (6.626 x 10^-34) x (3 x 10^8) / λ    (from (1) )

now just solve this and you will get

λ=12.14 x 10^-8

 =1.214 x 10^-7 i.e option a

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