Question

Energy of H atom in ground state is 13.6eV hence energy in second excited state is?

Answer 1

HELLO THERE!

For Hydrogen atom, Energy in nth orbit is given as:

$E_{n} = E_{1} \times n^{2}\\\\= -13.6 \times n^{2}$

Now, we are told to find the energy in 2nd excited state, which means n = 3.

So,

$E_{5} = -13.6 \times 9 = -122.4 eV atom^{-1}$

That's your answer...

Thanks!

Answer 2

Answer:

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