Question

Energy of H-atom in the ground state is
-13.6ev,hence energy in the second excited state is....

Answer 1

Answer:

-1.51 eV is the answer......

Answer 2

Answer:

Here's the formula buddy.

E = -13.6/n²

For first orbital

E = -13.6 eV

For second orbit it will be

E = -13.6/4= -3.40eV

And so on..

It shows that energy of electron increases as it moves away from nucleus and becomes zero when it reaches to infinity.

Hope it will help you!