Question

Energy of hydrogen atom in its ground state is -13.6 electron volt energy in fourth excited state is

Answer 1

HELLO THERE!

For Hydrogen atom, Energy in nth orbit is given as:

$E_{n} = E_{1} \times n^{2}\\\\= -13.6 \times n^{2}$

Now, we are told to find the energy in 4th excited state, which means n = 5.

So,

$E_{5} = -13.6 \times 25 = -340 eV atom^{-1}$

That's your answer...

Thanks!