Question

energy of photon with a wavelength 450nm in ergs

Answer 1

Explanation:

$e = \frac{hc}{lambda}$

h= 6.626 * 10^-34 J/sec

= 6.626 * 10^-34 * 10^-7 ergs/sec

= 6.626 * 10^-27 ergs)sec

c= speed of light = 3 *10^10 cm/sec

lambda= wavelength = 450 nm

=45 *10^-6cm

E= (6.626*10^-27*3 * 10^10)/ 45 * 10^-6

=0.44173 * 10^-27+10-(-6)

= 44.173 * 10^-9 ergs

Answer 2

Energy of a photon of light of wavelength 450 nm is calculated as  E=4.4×$10^{-19}$ joule

Explanation:

• The wavelength of the photon can be determined with the help the of energy of the photon
• The photon's electromagnetic frequency is directly proportional to the amount of energy or it can be said that it is inversely proportional to the wavelength.
• It can be calculated by using the formula E=hc/λ.
• Here in the equation, h is the Planck's constant, c is the speed of, light, and λ is the wavelength of the radiation.
• The energy of a single photon is hν or = (h/2π)ω where h is Planck's constant or it can be E= hc/λ
• E=6.62×$10^{-34}$ ×3×$10^{8}$ /450×$10^{9}$
• E=4.4×$10^{-19}$ joule

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