Energy of second bohr orbit of the hydrogen atom is
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Answer:
-3.4ev
Explanation:
E=-13.6×z^2/n^2
by putting values z=1 and n=2
E=-13.6×1/4
E=3.4 ev
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Answer:Energy of second bohr orbit of the hydrogen atom is -328 kj/mol.
Explanation:
E= -13.6 * (Z)2 / (n)2 eV
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