Question

Energy of two moles of photons of radiation with
frequency 5 x 1014 Hz is nearly
(1) 200 kJ
(2) 400 kJ
(3) 600 kJ
(4) 800 kJ​

Answer 1

Answer:

400kJ

Explanation:

$e = nhv$

n=2*6*10^23

h=6.7*10^-34Js

v=5*10^14Hz

e=nhv

e=4*10^5J