Physics, asked by yadavsudeep894, 1 month ago

Energy required for the electron excitation in Li++ from the first to the third Bohr orbit is

36.3eV
122.4eV
12.7eV
108.8eV​

Answers

Answered by manoranjanphy1
1

Explanation:

Energy in the nth orbit = - 13.6 z²/n²

in first orbit , n=1

= - 13.6 z²

in third orbit ,n=3

= - 13.6 z²/9

for Li ,z = 3

first orbit ,

= - 13.6 x 9

third orbit,

= -13.6

excitation energy = E3 - E1 = - 13.6 - ( -13.6 x 9)

= 13.6 ( 9 - 1) = 13.6 x 8 = 108.8 eV

Answered by Luit1
0

Answer:

Here is your answer

Explanation:

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