Question

Energy required for the ionization of 0.02 gram of magnesium is x kJ. What is the amount of energy required to ionise 1 atom of magnesium? ??

Please reply fast....

Answer 1

Given:

Weight of magnesium = 0.02g

Molecular mass of magnesium = 24g (Standard value)

To find:

Amount of energy required to ionize 1 atom of magnesium = ?

Calculation:

To calculate number of atoms,

Number of moles = $\frac{Weight}{Molecular mass} = \frac{0.02}{24} = \frac{1}{1200}$

Number of atoms in $\frac{1}{1200}$ moles of magnesium = $\frac{1}{1200} \times N_A$   ($N_A$ denotes avagadro's number).

∴ Energy required for the ionisation of 1 atom = $\frac{x}{(\frac{1}{1200}\times N_A)}$ = $\frac{x\times 10^3 }{0.02N_A}$

Conclusion:

The amount of energy required to ionize 1 atom of magnesium is $\frac{x\times 10^3 }{0.02N_A}$

Learn more about such concept

The energy required to ionise 2 mole of gaseous he+ ion present in its ground state is :

54.4 eV

​108.8NaeV

54.4NaeV

108.8eV

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