Energy required to dislodge electrons from excited isolated h atom
Answers
Answered by
9
The minimum amount of energy required to dislodge an electron from an atom is known as Ionization energy.
In our case we have Hydrogen.
For it to lose an electron, it requires to absorb ionization energy.
The ionization energy of hydrogen at ground state is - 13eV.
This is the minimum amount of energy required to dislodge an electron from a hydrogen atom.
The negative sign indicates that the process involves absorption of energy.
It's an endothermic process.
In our case we have Hydrogen.
For it to lose an electron, it requires to absorb ionization energy.
The ionization energy of hydrogen at ground state is - 13eV.
This is the minimum amount of energy required to dislodge an electron from a hydrogen atom.
The negative sign indicates that the process involves absorption of energy.
It's an endothermic process.
Answered by
18
Answer:
As H-atom's Ionisation Energy is 13.6..
So, According to the question,
We do need to find the ionisation energy from 1st excited state which is 2nd state..
The energy of 2nd state of H-atom is - 3.4..
So the energy we need to dislodge the electron will be lesser then or equal to 3.4 eV..
Hope it helps..
Similar questions