Question

Energy required to raise a liquid in a capillary tube

Answer 1

I’m sure there is some application of Kirchhoff's laws that can be used to solve this but I’ll just use basic resistance formulas for the solution. I am assuming the fourth resistor is connected in series with the other three. Each resistor is 8 ohms. The sum of 3 parallel resistances are (1/R1) + 1/(R2) + (1/R3) = 1/Rtotal. The three parallel resistances total resistance are 3 x(1/8) = 1/Rtotal. Solving for Rtotal you get 2.7 ohms. Connecting that in series with the 4th, 8 ohm resistor gives you a total resistance of 10.7 ohms, unless of course I am misinterpreting the problem.

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Pushpender Thakur

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