Energy required to remove an e-from M shell of
H-atom is 1.51 eV, then energy of first excited
state will be :-
(1) -1.51 eV
(2) +1.51 eV
(3) -3.4 eV
(4) -13.6 eV
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Answer:
using the formula -13.6/ n2 eV
-13.6/2^2 = -13.6/4
= -3.4 eV.
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