energy required to remove an e-from M shell of H-atom is 1.51 eV then energy of first excited state will be
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Answered by
19
Answer :
Formula : E = -13.6 Z²/n².
energy of first excited state = n=2.
Z=1(atomic number).
So, = -13.6/4
= - 3.4 ev.
The energy of first excited state will be -3.4ev.
pronita0:
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Answered by
2
Answer:
-3.4
Explanation:
just simple as tht....U can do in alternative way also En = -13.6/n²
En = -13.6/2²
En = -13.6/4
En = -3.4ev
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