Question

energy required to remove an e-from M shell of H-atom is 1.51 eV then energy of first excited state will be

Answer 1

Answer :

Formula : E = -13.6 Z²/n².

energy of first excited state = n=2.

Z=1(atomic number).

So, = -13.6/4

= - 3.4 ev.

The energy of first excited state will be -3.4ev.

Answer 2

Answer:

-3.4

Explanation:

just simple as tht....U can do in alternative way also En = -13.6/n²

En = -13.6/2²

En = -13.6/4

En = -3.4ev