Question

Energy required to stop the ejection of electrons from Cu plate is 0.24 eV. Calculate the
function when radiations of a = 253.7 nm strikes the plate.​

Answer 1

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Energy of photon =work function 1212mu2mu2

Energy of photon =work function ev0ev0------(1)

Where e is electronic charge and v0v0 is stopping potential and ev0ev0 is equal to energy required to stop the ejection of electron.

Ephoton=hcλEphoton=hcλ

⇒6.625×10−34×3.0×108253.7×10−9⇒6.625×10−34×3.0×108253.7×10−9

⇒7.834×10−19J⇒7.834×10−19J

⇒7.834×10−191.602×10−19⇒7.834×10−191.602×10−19eV=4.89eV

By equation (1)

4.894.89=work function +0.24

Work function =(4.89-0.24)eV

Work function =4.65ev

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