Question

Energy stored in a coil of inductance 50mH and current 2A

Answer 1

L = 50 mH = 50*10^-3 H
I = 2 A

We know that,

Energy stored in a inductor Coil = 0.5*L*I²

= 0.5*50*10^-3*2

= 50*10^-3 J

Hope it Helps!

Answer 2

Given data

L = 50mH = 0.5H

I = 2A

Answer

Energy stored in the coil = 1/2 * L * I²

                                         = 1/2 * 0.5 *2²

                                         = 0.5 * 0.5 * 4

                                         = 0.25 * 4

                                         = 1 J

So the energy stored in the coil is 1 J