Question

Energy stored per unit volume in a stretched wire having young's modulus y and stress s is

Answer 1

Answer : given that,

Young's modulus = y

stress = s

We know,

The energy stored per unit volume

$E=\dfrac{1}{2}\times stress\times strain$

$E=\dfrac{1}{2}\times \dfrac{stress\times{stress}}{y}$

$E=\dfrac{1}{2}\times \dfrac{s^{2}}{y}$

Hence, the energy stored per unit volume is

$E=\dfrac{1}{2}\times \dfrac{s^{2}}{y}$

Answer 2

$\frac{energy1}{energy2} = \frac{1}{2} \frac{(stress) {}^{2} }{y} = \alpha {}^{2} \frac{1}{2y}$

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