Question

engine of a car produce a maximum acceleration 2m/s^2 and it's breaks can produce maximum retardation of 3m/s^2 minimum time in which the car can travel a distance 6 km​

Answer 1

Answer:

Distance = 1/2*a*t*t

Distance = 6 km = 6000 m

So,

6000 = 1/2*2*t*t

t*t = 6000

t = 77.46 sec