Question

Engine of a train exerts a force of 6000N. If total mass of the train and the engine be 18000 kg and initially the train was standing on the platform, what is the magnitude of velocity attained by the train 20 second after the start ? Assume that there is no frictional force between railway track and train and motion is in a horizontal direction.​.

Answer 1

Answer:

Force exerted by engine, F = 6000N

Total mass, M = 18000kg

Hence acceleration of the train, a= F/M=1/3m/s^2

Given:

u=0

t=20 seconds

Assuming the acceleration to be constant, we use 1st equation of motion.

v=u + at

v=0 + 1/3×20= 6.66m/s.

So the answer is 6.66 m/s.

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Answer 2

Answer:6.67ms^-1

Explanation:u=0 ,v=?

m=