English a can do a piece of work in 90 days, b can do it in 40 days and c can do it in 12 days. each one of them works for a day turn-by-turn. on the first day, a works alone, on the second day, b works alone and on the third day, c works alone. after that, this cycle is repeated till the work is finished. they get rs. 240 for this job. if the wages are divided in proportion to the work that each has done, then find the amount that each of them will get.
Answers
Answered by
0
please do the Google search
Answered by
1
A=1/90. ,B=1/40 ,C=1/12
A,B,C can do the work in 3days=1/90+1/40+1/12
=43/360
A,B,C can do the work in 24days=43/360×8=43/45
remaining work =1-43/45=2/45
25th day remaining work=2/45-1/90=1/30
26th day 1/30-1/40=1/120
C can do 1/120 work in 1/10 day
total days= 26+1/10
A = 9days B=9days C=8+1/10 days
A. 9×1/90=1/10.
B 9×1/40= 9/40
C 1/12×81/10 = 27/40
so
A will get 1/10×240=24 ₹
B will get 9/40×240 =54₹
C will get 27/40 × 240 =162₹
Similar questions